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+/*
+* barrier -- mouse and keyboard sharing utility
+* Copyright (C) 2018 Debauchee Open Source Group
+*
+* This package is free software; you can redistribute it and/or
+* modify it under the terms of the GNU General Public License
+* found in the file LICENSE that should have accompanied this file.
+*
+* This package is distributed in the hope that it will be useful,
+* but WITHOUT ANY WARRANTY; without even the implied warranty of
+* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
+* GNU General Public License for more details.
+*
+* You should have received a copy of the GNU General Public License
+* along with this program. If not, see <http://www.gnu.org/licenses/>.
+*/
+
+/*
+
+These functions cover the vast majority of cases for different paths across
+windows and unixes. They are not, however, fullproof and probably don't cover
+fringe cases very well. The library below might be used as an alternative if
+these implementations prove to be insufficient. As the library's readme states
+it is simply a temporary band-aid until std::filesystem is integrated (C++17
+has it in std::experimental) and this class should also be treated as such.
+
+https://github.com/wjakob/filesystem/
+
+*/
+
+#include "PathUtilities.h"
+
+// keep the default platform delimiter as the first in the list
+#ifdef _WIN32
+static const char *Delimiters = "\\/";
+#else
+static const char *Delimiters = "/";
+#endif
+
+static const char DefaultDelimiter = Delimiters[0];
+
+std::string PathUtilities::basename(const std::string& path)
+{
+ return path.substr(path.find_last_of(Delimiters) + 1);
+}
+
+std::string PathUtilities::concat(const std::string& left, const std::string& right)
+{
+ // although npos is usually (-1) we can't count on that so handle it explicitly
+ auto leftEnd = left.find_last_not_of(Delimiters);
+ if (leftEnd == std::string::npos)
+ leftEnd = 0;
+ else
+ ++leftEnd;
+ auto rightStart = right.find_first_not_of(Delimiters, 0);
+ if (rightStart == std::string::npos) {
+ // both left/right are empty
+ if (left.size() == 0 && right.size() == 0)
+ return "";
+ // right is full of delims, left is okay
+ if (leftEnd > 0)
+ return left.substr(0, leftEnd);
+ // both left/right useless but at least one has delims
+ return std::string(1, DefaultDelimiter);
+ }
+ if (leftEnd == 0) {
+ // right is okay and not prefixed with delims, left is empty
+ if (left.size() == 0 && rightStart == 0)
+ return right.substr(rightStart);
+ // (right is okay and prefixed with delims) OR left is full of delims
+ return DefaultDelimiter + right.substr(rightStart);
+ }
+ // concatenation using both left and right
+ return left.substr(0, leftEnd) + DefaultDelimiter + right.substr(rightStart);
+}